Commit 542f1227 authored by henry's avatar henry Committed by Dan Ballard
Browse files

fixup! BB 42305: Add script to combine translation files across versions. 

TB 44498: Change the expected browser version gap between stable and
alpha from 0.5 to 1.0.
parent 509cdf3a

tools/base_browser/l10n/combine-translation-versions.py

+7 −25
Original line number Diff line number Diff line
@@ -103,10 +103,11 @@ class BrowserBranch: 


        self.name = branch_name

        self.prefix = version_match.group("prefix")

        self.browser_version = version_match.group("browser")

        browser_version_str = version_match.group("browser")

        self.browser_version = float(browser_version_str)

        # Convert tor-browser to "Tor Browser", and similar.

        browser_name = self.prefix.replace("-", " ").title()

        self.browser_version_name = f"{browser_name} {self.browser_version}"

        self.browser_version_name = f"{browser_name} {browser_version_str}"



        self._is_head = is_head

        self._ref = "HEAD" if is_head else f"origin/{branch_name}"
@@ -114,7 +115,7 @@ class BrowserBranch: 
        firefox_nums = [int(n) for n in version_match.group("firefox").split(".")]

        if len(firefox_nums) == 2:

            firefox_nums.append(0)

        browser_nums = [int(n) for n in self.browser_version.split(".")]

        browser_nums = [int(n) for n in browser_version_str.split(".")]

        branch_number = int(version_match.group("number"))

        # Prioritise the firefox ESR version, then the browser version then the

        # branch number.
@@ -127,25 +128,8 @@ class BrowserBranch: 
            branch_number,

        )



        # Minor version for browser is only ever "0" or "5", so we can convert

        # the version to an integer.

        self._browser_int_version = int(2 * float(self.browser_version))



        self._file_paths: list[str] | None = None



    def release_below(self, other: "BrowserBranch", num: int) -> bool:

        """Determine whether another branch is within range of a previous

        browser release.



        The browser versions are expected to increment by "0.5", and a previous

        release branch's version is expected to be `num * 0.5` behind the

        current one.



        :param other: The branch to compare.

        :param num: The number of "0.5" releases behind to test with.

        """

        return other._browser_int_version == self._browser_int_version - num



    def __lt__(self, other: "BrowserBranch") -> bool:

        return self._ordered < other._ordered
@@ -262,16 +246,14 @@ def get_stable_branch( 
            # Stable can be one release version behind.

            # NOTE: In principle, when switching between versions there may be a

            # window of time where the development branch has not yet progressed

            # to the next "0.5" release, so has the same browser version as the

            # to the next ".0" release, so has the same browser version as the

            # stable branch. So we also allow for matching browser versions.

            # NOTE:

            # 1. The "Will be unused in" message will not make sense, but we do

            #    not expect string differences in this scenario.

            # 2. We do not expect this scenario to last for long.

            if not (

                compare_version.release_below(branch, 1)

                or compare_version.release_below(branch, 0)

            ):

            release_diff = compare_version.browser_version - branch.browser_version

            if release_diff < 0.0 or release_diff > 1.0:

                continue

            stable_branches.append(branch)

        elif is_legacy: